Q. [ 5/10 ]
320°F = ... °R
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[tex] = ( {320}^{ \circ} - {32}^{ \circ} ) \times \frac{4}{9} [/tex]
[tex] = {288}^{ \circ} \times \frac{4}{9} [/tex]
[tex] = { \frac{1.152}{9} }^{ \circ} [/tex]
= 128°
AF࿐
Jawaban:
320°F = ... °R
(°Ré) = (S(°F) - 32) × 4/9
(°Ré) = (320°F - 32) × 4/9
(°Ré) = 288 × 4/9
(°Ré) = 128°R
